JEE MAIN - Chemistry (2021 - 1st September Evening Shift - No. 17)
The sum of oxidation states of two silver ions in [Ag(NH3)2] [Ag(CN)2] complex is _____________.
Answer
2
Explanation
[Ag(NH3)2][Ag(CN)2] complex dissociates into [Ag(NH3)2]+ and [Ag(CN)2].
Oxidation of Ag in [Ag(NH3)2]+
Ag + 0 $$\times$$ 2 = + 1
Ag = + 1
Oxidation state of Ag in [Ag(CN)2]$$-$$
Ag + ($$-$$1) $$\times$$ 2 = $$-$$ 1
Ag $$-$$ 2 = $$-$$ 1
$$\Rightarrow$$ Ag = + 1
$$\therefore$$ Sum of oxidation states of two silver ions in [Ag(NH3)2][Ag(CN)2] complex is 2.
Oxidation of Ag in [Ag(NH3)2]+
Ag + 0 $$\times$$ 2 = + 1
Ag = + 1
Oxidation state of Ag in [Ag(CN)2]$$-$$
Ag + ($$-$$1) $$\times$$ 2 = $$-$$ 1
Ag $$-$$ 2 = $$-$$ 1
$$\Rightarrow$$ Ag = + 1
$$\therefore$$ Sum of oxidation states of two silver ions in [Ag(NH3)2][Ag(CN)2] complex is 2.
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