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JEE MAIN - Chemistry (2021 - 17th March Morning Shift - No. 19)

0.01 moles of a weak acid HA (Ka = 2.0 $$\times$$ 10$$-$$6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is __________ $$\times$$ 10$$-$$5 (Round off to the Nearest Integer).

[Neglect volume change on adding HA. Assume degree of dissociation <<1 ]
Answer
2

Explanation

JEE Main 2021 (Online) 17th March Morning Shift Chemistry - Chemical Equilibrium Question 54 English Explanation

Now,

$${K_a} = {{[{H^ + }][{A^ - }]} \over {[HA]}}$$

$$ \Rightarrow 2 \times {10^{ - 6}} = {{(0.1)({{10}^{ - 2}}\alpha )} \over {{{10}^{ - 2}}}}$$

$$ \Rightarrow \alpha = 2 \times {10^{ - 5}}$$

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