JEE MAIN - Chemistry (2021 - 17th March Morning Shift - No. 17)
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In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ________%. (Round off to the Nearest Integer).
(Given atomic mass : C : 12.0 u, H : 1.0 u, O : 16.0 u, N : 14.0 u)
Answer
80
Explanation
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Weight of (C6H5NO2)Theoretical = $${{{3.9} \over {78}} \times 123}$$ = 6.15 g
% yield of reaction = $${{{W_{actual}}} \over {{W_{theoretical}}}} \times 100 = {{4.92} \over {6.15}} \times = 80\% $$
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