JEE MAIN - Chemistry (2021 - 17th March Evening Shift - No. 14)

On complete reaction of FeCl₃ with oxalic acid in aqueous solution containing KOH, resulted in the formation of product A. The secondary valency of Fe in the product A is __________. (Round off to the Nearest Integer).

Answer

Explanation

FeCl₃ + 3H₂C₂O₄ + 6KOH $$ \to $$ K₃[Fe(C₂O₄)₃] + 3KCl + 6H₂O JEE Main 2021 (Online) 17th March Evening Shift Chemistry - Coordination Compounds Question 175 English Explanation

Coordination number = 6

Secondary valency is 6

JEE MAIN - Chemistry (2021 - 17th March Evening Shift - No. 14)

Explanation

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