JEE MAIN - Chemistry (2021 - 17th March Evening Shift - No. 10)
Match List - I with List - II :
Choose the correct answer from the options given below :
| List - I |
List - II |
||
|---|---|---|---|
| (a) | $$[Co{(N{H_3})_6}][Cr{(CN)_6}]$$ | (i) | Linkage isomerism |
| (b) | $$[Co{(N{H_3})_3}{(N{O_2})_3}]$$ | (ii) | Solvate isomerism |
| (c) | $$[Cr{({H_2}O)_6}C{l_3}$$ | (iii) | Co-ordination isomerism |
| (d) | $$cis - {[CrC{l_2}{(ox)_2}]^{3 - }}$$ | (iv) | Optical isomerism |
Choose the correct answer from the options given below :
(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
(a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
Explanation
(a) [Co(NH3)6][Cr(CN)6] $$ \to $$ (iii) Coordination isomerism
(b) [Co(NH3)3(NO2)3] $$ \to $$ (i) Linkage isomerism
(c) [Cr(H2O)6]Cl3 $$ \to $$ (ii) Solvate isomerism
(d) cis-[CrCl2(ox)2]3– $$ \to $$ (iv) Optical isomerism
(b) [Co(NH3)3(NO2)3] $$ \to $$ (i) Linkage isomerism
(c) [Cr(H2O)6]Cl3 $$ \to $$ (ii) Solvate isomerism
(d) cis-[CrCl2(ox)2]3– $$ \to $$ (iv) Optical isomerism
Comments (0)
