JEE MAIN - Chemistry (2021 - 17th March Evening Shift - No. 1)
$${C_{12}}{H_{22}}{O_{11}} + {H_2}O\buildrel {Enzyme\,A} \over
\longrightarrow \mathop {{C_6}{H_{12}}{O_6}}\limits_{Glu\cos e} + \mathop {{C_6}{H_{12}}{O_6}}\limits_{Fructose} $$
$$\mathop {{C_6}{H_{12}}{O_6}}\limits_{Glu\cos e} \buildrel {Enzyme\,B} \over \longrightarrow 2{C_2}{H_5}OH + 2C{O_2}$$
In the above reactions, the enzyme A and enzyme B respectively are :
$$\mathop {{C_6}{H_{12}}{O_6}}\limits_{Glu\cos e} \buildrel {Enzyme\,B} \over \longrightarrow 2{C_2}{H_5}OH + 2C{O_2}$$
In the above reactions, the enzyme A and enzyme B respectively are :
Zymase and Invertase
Invertase and Amylase
Amylase and Invertase
Invertase and Zymase
Explanation
_17th_March_Evening_Shift_en_1_1.png)
$$ \therefore $$ Enzyme A is Invertase
Enzyme B is Zymase
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