JEE MAIN - Chemistry (2020 - 9th January Morning Slot - No. 17)
Complex X of composition Cr(H2O)6Cln
has a spin only magnetic moment of 3.83
BM. It reacts with AgNO3 and shows
geometrical isomerism. The IUPAC
nomenclature of X is :
Hexaaqua chromium (III) chloride
Tetraaquadichlorido chromium(IV)
chloride dihydrate
Tetraaquadichlorido chromium (III)
chloride dihydrate
Dichloridotetraaqua chromium (IV)
chloride dihydrate
Explanation
Given complex Cr(H2O)6Cln
As the magnetic mement is 3.83 BM then
Spin only magnetic moment = $$\sqrt {n\left( {n + 2} \right)} $$ BM = 3.83
$$ \Rightarrow $$ n = 3
Chromium in +3 oxidation state so molecular formula is Cr(H2O)6Cln.
$$ \therefore $$ This formula have following isomers
(a) [Cr(H2O)6]Cl3 : react with AgNO3 but does not show geometrical isomerism.
(b) [Cr(H2O)5Cl]Cl2.H2O react with AgNO3 but does not show geometrical isomerism.
(c) [Cr(H2O)4Cl2]Cl.2H2O react with AgNO3 & show geometrical isomerism.
(d) [Cr(H2O)3Cl3].3H2O does not react with AgNO3 & show geometrical isomerism.
Compound will be [Cr(H2O)4Cl2] Cl.2H2O
IUPAC NAME : Tetraaquadichlorido chromium(III) chloride dihydrate
As the magnetic mement is 3.83 BM then
Spin only magnetic moment = $$\sqrt {n\left( {n + 2} \right)} $$ BM = 3.83
$$ \Rightarrow $$ n = 3
Chromium in +3 oxidation state so molecular formula is Cr(H2O)6Cln.
$$ \therefore $$ This formula have following isomers
(a) [Cr(H2O)6]Cl3 : react with AgNO3 but does not show geometrical isomerism.
(b) [Cr(H2O)5Cl]Cl2.H2O react with AgNO3 but does not show geometrical isomerism.
(c) [Cr(H2O)4Cl2]Cl.2H2O react with AgNO3 & show geometrical isomerism.
(d) [Cr(H2O)3Cl3].3H2O does not react with AgNO3 & show geometrical isomerism.
Compound will be [Cr(H2O)4Cl2] Cl.2H2O
IUPAC NAME : Tetraaquadichlorido chromium(III) chloride dihydrate
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