JEE MAIN - Chemistry (2020 - 9th January Evening Slot - No. 6)
10.30 mg of O2 is dissolved into a liter of sea
water of density 1.03 g/mL. The concentration
of O2 in ppm is__________.
Answer
10
Explanation
1030 gm of sea water contains = 10.3 Ć 10ā3 gm
106 gm of sea water contains = $${{10.3 \times {{10}^{ - 3}}} \over {1030}} \times {10^6}$$ = 10 ppm
106 gm of sea water contains = $${{10.3 \times {{10}^{ - 3}}} \over {1030}} \times {10^6}$$ = 10 ppm
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