JEE MAIN - Chemistry (2020 - 9th January Evening Slot - No. 15)
5 g of zinc is treated separately with an excess
of
(a) dilute hydrochloric acid and
(b) aqueous sodium hydroxide.
The ratio of the volumes of H2 evolved in these two reactions is :
(a) dilute hydrochloric acid and
(b) aqueous sodium hydroxide.
The ratio of the volumes of H2 evolved in these two reactions is :
1 : 2
1 : 1
1 : 4
2 : 1
Explanation
Zn + 2dil. HCl $$ \to $$ ZnCl2 + H2
Zn + 2NaOH $$ \to $$ Na2ZnO2 + H2
From one mole of Zn, 1 mol of H2 is produced by both NaOH and HCl.
The ratio of the volume of H2 is 1 : 1
Zn + 2NaOH $$ \to $$ Na2ZnO2 + H2
From one mole of Zn, 1 mol of H2 is produced by both NaOH and HCl.
The ratio of the volume of H2 is 1 : 1
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