JEE MAIN - Chemistry (2020 - 8th January Morning Slot - No. 7)
The magnitude of work done by a gas that undergoes a reversible expansion along the path ABC shown in
the figure is _______.
_8th_January_Morning_Slot_en_7_1.png)
Answer
48
Explanation
Work done = Area covered by the diagram
= $$1\over2$$ × (sum of parallel sides) × height
= $$1\over2$$ × (10+6) × 6
= $$1\over2$$ × 16 × 6
= 48 Joule
Note : Here pressure difference = 8 - 2 = 6 Pa and volume difference = 12 - 2 = 10
= $$1\over2$$ × (sum of parallel sides) × height
= $$1\over2$$ × (10+6) × 6
= $$1\over2$$ × 16 × 6
= 48 Joule
Note : Here pressure difference = 8 - 2 = 6 Pa and volume difference = 12 - 2 = 10
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