JEE MAIN - Chemistry (2020 - 8th January Morning Slot - No. 2)
A graph of vapour pressure and temperature for three different liquids X, Y, and Z is shown below :
_8th_January_Morning_Slot_en_2_1.png)
The following inferences are made :
(A) X has higher intermolecular interactions compared to Y.
(B) X has lower intermolecular interactions compared to Y.
(C) Z has lower intermolecular interactions compared to Y.
The correct inference (s) is / are :
The following inferences are made :
(A) X has higher intermolecular interactions compared to Y.
(B) X has lower intermolecular interactions compared to Y.
(C) Z has lower intermolecular interactions compared to Y.
The correct inference (s) is / are :
(B)
(A)
(C)
(A) and (C)
Explanation
Vapour pressure of a liquid at a given
temperature is inversely proportional to
intermolecular force of attraction. At the same
temperature, vapour pressure of X is higher
than that of Y.
Therefore (X) has lower intermolecular interactions compared to Y. Statement (B) is correct.
Therefore (X) has lower intermolecular interactions compared to Y. Statement (B) is correct.
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