JEE MAIN - Chemistry (2020 - 8th January Morning Slot - No. 1)
The third ionization enthalpy is minimum for :
Ni
Co
Mn
Fe
Explanation
Electronic configuration of
25Mn = [Ar]3d54s2
25Mn2+ = [Ar]3d54s0
26Fe = [Ar]3d64s2
26Fe2+ = [Ar]3d64s0
27Co = [Ar]3d74s2
27Co2+ = [Ar]3d74s0
28Ni = [Ar]3d84s2
28Ni2+ = [Ar]3d84s0
So third ionisation energy is minimum for Fe.
25Mn = [Ar]3d54s2
25Mn2+ = [Ar]3d54s0
26Fe = [Ar]3d64s2
26Fe2+ = [Ar]3d64s0
27Co = [Ar]3d74s2
27Co2+ = [Ar]3d74s0
28Ni = [Ar]3d84s2
28Ni2+ = [Ar]3d84s0
So third ionisation energy is minimum for Fe.
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