JEE MAIN - Chemistry (2020 - 8th January Evening Slot - No. 18)
A metal (A) on heating in nitrogen gas gives
compound B. B on treatment with H2O gives
a colourless gas which when passed through
CuSO4 solution gives a dark blue-violet
coloured solution. A and B respectively, are :
Na and NaNO3
Na and Na3N
Mg and Mg3N2
Mg and Mg(NO3)2
Explanation
3Mg(A) + N2 $$\buildrel \Delta \over
\longrightarrow $$
Mg3N2(B) $$\buildrel {6{H_2}O} \over
\longrightarrow $$
3Mg(OH)2 + 2NH3 (colourless gas)
CuSO + 4NH3 $$ \to $$ [Cu(NH3)4]SO4 (deep blue solution)
3Mg(OH)2 + 2NH3 (colourless gas)
CuSO + 4NH3 $$ \to $$ [Cu(NH3)4]SO4 (deep blue solution)
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