JEE MAIN - Chemistry (2020 - 8th January Evening Slot - No. 13)
Hydrogen has three isotopes (A), (B) and (C).
If the number of neutron(s) in (A), (B) and (C)
respectively, are (x), (y) and (z), the sum of (x),
(y) an (z) is :
3
1
4
2
Explanation
Hydrogen has three isotopes
(A) Protium ($${}_1^1H$$) has 0 neutron.
(B) Deutrium ($${}_1^2H$$) has 1 neutrons.
(C) Tritium ($${}_1^3H$$) has 2 neutrons.
Total number of neutrons in three
isotopes of hydrogen = 0 + 1 + 2 = 3
(A) Protium ($${}_1^1H$$) has 0 neutron.
(B) Deutrium ($${}_1^2H$$) has 1 neutrons.
(C) Tritium ($${}_1^3H$$) has 2 neutrons.
Total number of neutrons in three
isotopes of hydrogen = 0 + 1 + 2 = 3
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