JEE MAIN - Chemistry (2020 - 7th January Morning Slot - No. 8)
Given that the standard potentials (Eo) of Cu2+/Cu and Cu+/Cu are 0.34 V and 0.522 V respectively, the Eo of Cu2+/Cu+ :
- 0.182 V
- 0.158 V
0.182 V
+0.158 V
Explanation
Cu+2 + 2e– $$ \to $$ Cu Eo = 0.34 V ....(1)
Cu+ + e– $$ \to $$Cu Eo = 0.522 V
Cu $$ \to $$ Cu+ + e– Eo = -0.522 V ...(2)
By adding (1) and (2) we get,
Cu+2 + e– $$ \to $$ Cu+
Eocell = $${{0.34 \times 2 + 1 \times \left( { - 0.522} \right)} \over 1}$$ = 0.158 V
Cu+ + e– $$ \to $$Cu Eo = 0.522 V
Cu $$ \to $$ Cu+ + e– Eo = -0.522 V ...(2)
By adding (1) and (2) we get,
Cu+2 + e– $$ \to $$ Cu+
Eocell = $${{0.34 \times 2 + 1 \times \left( { - 0.522} \right)} \over 1}$$ = 0.158 V
Comments (0)
