JEE MAIN - Chemistry (2020 - 7th January Morning Slot - No. 2)
Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound
(X) gives white precipitate with silver nitrate solution. The average bond order between CI and O
atoms in (Y) is.
Answer
1.66to1.67
Explanation
3Cl2 + 6NaOH $$ \to $$ 5NaCl + NaClO3 + 3H2O
NaCl + AgNO3 $$ \to $$ AgCl- $$ \downarrow $$ + NaNO3
$$ \therefore $$ X = NaCl then Y = NaClO3
Here in anion ClO3- has bond between Cl and O atom.
Bond order of Cl–O Bond =
= $${5 \over 3}$$ = 1.67
NaCl + AgNO3 $$ \to $$ AgCl- $$ \downarrow $$ + NaNO3
$$ \therefore $$ X = NaCl then Y = NaClO3
Here in anion ClO3- has bond between Cl and O atom.
Bond order of Cl–O Bond =
Total bond
Total resonating structure
.
= $${5 \over 3}$$ = 1.67
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