JEE MAIN - Chemistry (2020 - 7th January Evening Slot - No. 13)
The equation that is incorrect is :
$${\left( {\Lambda _m^0} \right)_{KCl}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaCl}} = {\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{KCl}}$$
$${\left( {\Lambda _m^0} \right)_{{H_2}O}} = {\left( {\Lambda _m^0} \right)_{HCl}} + {\left( {\Lambda _m^0} \right)_{NaOH}} - {\left( {\Lambda _m^0} \right)_{NaCl}}$$
Explanation
Left hand side :
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}}$$ = $${\left( {\Lambda _m^0} \right)_{Br^-}} - {\left( {\Lambda _m^0} \right)_{I^-}}$$ ....(1)
Right hand side :
$${\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$ = $${\left( {\Lambda _m^0} \right)_{K^+}} - {\left( {\Lambda _m^0} \right)_{Na^+}}$$ ....(2)
According to Kohlrausch's law option (B) is incorrect as (1) and (2) are not equal.
$${\left( {\Lambda _m^0} \right)_{NaBr}} - {\left( {\Lambda _m^0} \right)_{NaI}}$$ = $${\left( {\Lambda _m^0} \right)_{Br^-}} - {\left( {\Lambda _m^0} \right)_{I^-}}$$ ....(1)
Right hand side :
$${\left( {\Lambda _m^0} \right)_{KBr}} - {\left( {\Lambda _m^0} \right)_{NaBr}}$$ = $${\left( {\Lambda _m^0} \right)_{K^+}} - {\left( {\Lambda _m^0} \right)_{Na^+}}$$ ....(2)
According to Kohlrausch's law option (B) is incorrect as (1) and (2) are not equal.
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