JEE MAIN - Chemistry (2020 - 6th September Morning Slot - No. 15)
The species that has a spin-only magnetic
moment of 5.9 BM, is :
(Td = tetrahedral)
(Td = tetrahedral)
[MnBr4]2– (Td)
[NiCl4]2– (Td)
Ni(CO)4 (Td)
[Ni(CN)4]2– (square planar)
Explanation
_6th_September_Morning_Slot_en_15_1.png)
$$ \therefore $$ Unpaired electrons = 5
$$ \therefore $$ $$\mu $$ = $$\sqrt {5\left( {5 + 2} \right)} $$ = 5.9 BM
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