JEE MAIN - Chemistry (2020 - 5th September Morning Slot - No. 6)
The difference between the radii of 3rd and 4th
orbits of Li2+ is R1 . The difference between the
radii of 3rd and 4th orbits of He+ is $$\Delta $$R2 .
Ratio $$\Delta $$R1 : $$\Delta $$R2 is :
orbits of Li2+ is R1 . The difference between the
radii of 3rd and 4th orbits of He+ is $$\Delta $$R2 .
Ratio $$\Delta $$R1 : $$\Delta $$R2 is :
8 : 3
3 : 2
2 : 3
3 : 8
Explanation
Rn = a0$${{{n^2}} \over Z}$$
$${{\Delta {R_1}} \over {\Delta {R_2}}} = {{{{\left( {{r_4} - {r_3}} \right)}_{L{i^{2 + }}}}} \over {{{\left( {{r_4} - {r_3}} \right)}_{H{e^ + }}}}}$$
= $${{{{{4^2}} \over 3} - {{{3^2}} \over 3}} \over {{{{4^2}} \over 2} - {{{4^2}} \over 2}}}$$ = $${{7/3} \over {7/2}} = {2 \over 3}$$
$${{\Delta {R_1}} \over {\Delta {R_2}}} = {{{{\left( {{r_4} - {r_3}} \right)}_{L{i^{2 + }}}}} \over {{{\left( {{r_4} - {r_3}} \right)}_{H{e^ + }}}}}$$
= $${{{{{4^2}} \over 3} - {{{3^2}} \over 3}} \over {{{{4^2}} \over 2} - {{{4^2}} \over 2}}}$$ = $${{7/3} \over {7/2}} = {2 \over 3}$$
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