JEE MAIN - Chemistry (2020 - 5th September Morning Slot - No. 2)
The increasing order of basicity of the following
compounds is :
_5th_September_Morning_Slot_en_2_1.png)
(A) < (B) < (C) < (D)
(B) < (A) < (C) < (D)
(D) < (A) < (B) < (C)
(B) < (A) < (D) < (C)
Explanation
The compound which can donate lone pair more easily is more basic.
(A) N is sp2 hybridized and lone pair is localised means not perticipating in resonance.
(B) Here lone pair perticipates in resonance and involved in aromaticity. So this is weakest base.
(C) N is sp3 hybridized and lone pair is localised means not perticipating in resonance. As here N atom is sp3 hybridized so it is more basic than A and D.
(D) Here lone pair of 1st N atom perticipates in resonance but 2nd N is sp2 hybridized and lone pair is localised means not perticipating in resonance. So basisity will depend on 2nd N atom. Due to perticipatation in resonance of 1st N atom some negative charge is genareted on 2nd N atom which makes it more basic than compound A.
(A) N is sp2 hybridized and lone pair is localised means not perticipating in resonance.
(B) Here lone pair perticipates in resonance and involved in aromaticity. So this is weakest base.
(C) N is sp3 hybridized and lone pair is localised means not perticipating in resonance. As here N atom is sp3 hybridized so it is more basic than A and D.
(D) Here lone pair of 1st N atom perticipates in resonance but 2nd N is sp2 hybridized and lone pair is localised means not perticipating in resonance. So basisity will depend on 2nd N atom. Due to perticipatation in resonance of 1st N atom some negative charge is genareted on 2nd N atom which makes it more basic than compound A.
Comments (0)
