JEE MAIN - Chemistry (2020 - 5th September Evening Slot - No. 9)
Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol–1, and 4 kJ mol–1, respectively.
The hydration enthalpy of NaCl is :
The hydration enthalpy of NaCl is :
–780 kJ mol–1
–784 kJ mol–1
780 kJ mol–1
784 kJ mol–1
Explanation
$$\Delta $$Hsol = Lattice enthalpy + $$\Delta $$Hhyd
$$ \Rightarrow $$ 4 = 788 + $$\Delta $$Hhyd
$$ \Rightarrow $$ $$\Delta $$Hhyd = –784 kJ mol–1
$$ \Rightarrow $$ 4 = 788 + $$\Delta $$Hhyd
$$ \Rightarrow $$ $$\Delta $$Hhyd = –784 kJ mol–1
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