JEE MAIN - Chemistry (2020 - 5th September Evening Slot - No. 5)
For a reaction X + Y ⇌ 2Z , 1.0 mol of X, 1.5 mol
of Y and 0.5 mol of Z were taken in a 1 L vessel and
allowed to react. At equilibrium, the concentration
of Z was 1.0 mol L–1. The equilibrium constant of reaction
is $${x \over {15}}$$. The value of x is _________.
of Y and 0.5 mol of Z were taken in a 1 L vessel and
allowed to react. At equilibrium, the concentration
of Z was 1.0 mol L–1. The equilibrium constant of reaction
is $${x \over {15}}$$. The value of x is _________.
Answer
16
Explanation
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Keq = $${{{{\left( 1 \right)}^2}} \over {{3 \over 4} \times {5 \over 4}}}$$ = $${{16} \over {15}}$$
$$ \therefore $$ x = 16
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