JEE MAIN - Chemistry (2020 - 5th September Evening Slot - No. 3)
For a dimerization reaction,
2A(g) $$ \to $$ A2(g)
at 298 K, $$\Delta $$Uo = –20 kJ mol–1, $$\Delta $$So = –30 JK–1 mol–1,
then the $$\Delta $$Go will be _____ J.
2A(g) $$ \to $$ A2(g)
at 298 K, $$\Delta $$Uo = –20 kJ mol–1, $$\Delta $$So = –30 JK–1 mol–1,
then the $$\Delta $$Go will be _____ J.
Answer
-13540to-13537
Explanation
$$\Delta $$Go = $$\Delta $$Ho - T$$\Delta $$So
= ($$\Delta $$Uo + $$\Delta $$ngRT) - T$$\Delta $$So
= $$\left[ {\left\{ { - 20 + \left( 1 \right){{8.314} \over {1000}} \times 298} \right\} - {{298} \over {1000}} \times \left( { - 30} \right)} \right]$$ kJ
= – 13.537572 kJ
= – 13537.57 Joule
= ($$\Delta $$Uo + $$\Delta $$ngRT) - T$$\Delta $$So
= $$\left[ {\left\{ { - 20 + \left( 1 \right){{8.314} \over {1000}} \times 298} \right\} - {{298} \over {1000}} \times \left( { - 30} \right)} \right]$$ kJ
= – 13.537572 kJ
= – 13537.57 Joule
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