JEE MAIN - Chemistry (2020 - 4th September Morning Slot - No. 6)
The mass of ammonia in grams produced when
2.8 kg of dinitrogen quantitatively reacts with 1
kg of dihydrogen is _______.
Answer
3400
Explanation
N2(g) + 3H2(g) $$ \to $$ 2NH3(g)
Number of moles of N2 = $${{2.8 \times {{10}^3}} \over {28}}$$ = 100
Number of moles of H2 = $${{1000} \over 2}$$ = 500
Here N2 is limiting reagent.
$$ \therefore $$ Number of moles of NH3 produced = 2 $$ \times $$ 100 = 200
Mass of NH3 produced = 200 × 17 = 3400 gm
Number of moles of N2 = $${{2.8 \times {{10}^3}} \over {28}}$$ = 100
Number of moles of H2 = $${{1000} \over 2}$$ = 500
Here N2 is limiting reagent.
$$ \therefore $$ Number of moles of NH3 produced = 2 $$ \times $$ 100 = 200
Mass of NH3 produced = 200 × 17 = 3400 gm
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