JEE MAIN - Chemistry (2020 - 4th September Evening Slot - No. 8)
The osmotic pressure of a solution of NaCl is
0.10 atm and that of a glucose solution is
0.20 atm. The osmotic pressure of a solution
formed by mixing 1 L of the sodium chloride
solution with 2 L of
the glucose solution is x $$ \times $$ 10–3 atm. x is _____. (nearest integer)
the glucose solution is x $$ \times $$ 10–3 atm. x is _____. (nearest integer)
Answer
167
Explanation
For NaCl : $$\pi $$1 = 0.1 atm, v1 = 1 L
For Glucose: $$\pi $$2 = 0.2 atm, v2 = 2 L
$$\pi $$mix = $${{{\pi _1}{v_1} + {\pi _2}{v_2}} \over {{v_1} + {v_2}}}$$
= $${{0.1 \times 1 + 0.2 \times 2} \over {1 + 2}}$$
= $${{0.5} \over 3}$$ = $${{500} \over 3} \times {10^{ - 3}}$$
= 167 $$ \times $$ 10-3 atm
For Glucose: $$\pi $$2 = 0.2 atm, v2 = 2 L
$$\pi $$mix = $${{{\pi _1}{v_1} + {\pi _2}{v_2}} \over {{v_1} + {v_2}}}$$
= $${{0.1 \times 1 + 0.2 \times 2} \over {1 + 2}}$$
= $${{0.5} \over 3}$$ = $${{500} \over 3} \times {10^{ - 3}}$$
= 167 $$ \times $$ 10-3 atm
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