JEE MAIN - Chemistry (2020 - 4th September Evening Slot - No. 6)
The one that can exhibit highest paramagnetic
behaviour among the following is :
gly = glycinato; bpy = 2, 2'-bipyridine
gly = glycinato; bpy = 2, 2'-bipyridine
[Fe(en)(bpy)(NH3)2]2+
[Pd(gly)2]
[Co(OX)2(OH)2]ā ($$\Delta $$0 > P)
[Ti(NH3)6]3+
Explanation
[Co(OX)2(OH)2]ā
(As here $$\Delta $$0 > P so those ligands act as strong field ligand and pairing happens.)
27Co+5 = [18Ar] 3d4 4s0( $$t_{2g}^{2,1,1},e_g^{0,0}$$ )
It has highest number of unpaired eā s. so it is most paramagnetic.
(As here $$\Delta $$0 > P so those ligands act as strong field ligand and pairing happens.)
27Co+5 = [18Ar] 3d4 4s0( $$t_{2g}^{2,1,1},e_g^{0,0}$$ )
It has highest number of unpaired eā s. so it is most paramagnetic.
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