JEE MAIN - Chemistry (2020 - 4th September Evening Slot - No. 18)
Five moles of an ideal gas at 1 bar and 298 K
is expanded into vacuum to double the volume.
The work done is :
Zero
-RT $$\ln {{{V_2}} \over {{V_1}}}$$
CV (T2 – T1)
– RT (V2 – V1)
Explanation
As the expansion is done in vacuum that is in absence
of pext so pext = 0
$$ \therefore $$ W = - pext$$\Delta $$V
= 0
of pext so pext = 0
$$ \therefore $$ W = - pext$$\Delta $$V
= 0
Comments (0)
