JEE MAIN - Chemistry (2020 - 4th September Evening Slot - No. 11)

Consider the following equations :
2Fe2+ + H2O2 $$ \to $$ xA + yB
(in basic medium)
2MnO4- + 6H+ + 5H2O2 $$ \to $$ x'C + y'D + z'E
(in acidic medium)
The sum of the stoichiometric coefficients x, y, x', y', and z' for products A, B, C, D and E, respectively, is ______.
Answer
19

Explanation

2Fe2+ + H2O2 $$ \to $$ 2Fe3+ + 2OH–

2MnO4- + 6H+ + 5H2O2 $$ \to $$ 2Mn2+ + 8H2O + 5O2

$$ \therefore $$ x + y + x' + y' + z' = 19

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