JEE MAIN - Chemistry (2020 - 3rd September Evening Slot - No. 1)

The d-electron configuration of [Ru(en)3 ]Cl2
and [Fe(H2O)6]Cl2 , respectively are :
$$t_{2g}^4e_g^2$$ and $$t_{2g}^6e_g^0$$
$$t_{2g}^6e_g^0$$ and $$t_{2g}^6e_g^0$$
$$t_{2g}^6e_g^0$$ and $$t_{2g}^4e_g^2$$
$$t_{2g}^4e_g^2$$ and $$t_{2g}^4e_g^2$$

Explanation

[Ru(en)3 ]Cl2 :

Here CN = 6 so octahedral splitting happens.

'en' is strong field ligand so $$\Delta $$0 > P(pairing energy). That is why pairing of electrons happens.

$$\Delta $$0 = Energy gap between eg and t2g orbital.


[Fe(H2O)6]Cl2 :

Here CN = 6 so octahedral splitting happens.

H2O is weak field ligand so $$\Delta $$0 < P(pairing energy). That is why no pairing of electrons happens.

$$\Delta $$0 = Energy gap between eg and t2g orbital.

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