JEE MAIN - Chemistry (2020 - 2nd September Morning Slot - No. 2)
The oxidation states of iron atoms in
compounds (A), (B) and (C), respectively, are x,
y and z. The sum of x, y and z is ________.
Na4[Fe(CN)5(NOS)]
(A)
Na4[FeO4]
(B)
[Fe2(CO)9]
(C)
Na4[Fe(CN)5(NOS)]
(A)
Na4[FeO4]
(B)
[Fe2(CO)9]
(C)
Answer
6
Explanation
Na4[Fe(CN)5(NOS)]
Let the O.S. of Fe be x
OS of CN = –1
OS of NOS = –1
$$ \therefore $$ (+1)4 + x + (–1)5 + (–1)1 = 0
$$ \Rightarrow $$ x = +2
Na4[FeO4]
Let O.S. of Fe be y
(+1)4 + y + (–2)4 = 0
$$ \Rightarrow $$ y = +4
[Fe2(CO)9]
Let O.S. of Fe be z
2z + 0 × 9 = 0
$$ \Rightarrow $$ z = 0
so (x + y + z) = +2 + 4 + 0 = 6
Let the O.S. of Fe be x
OS of CN = –1
OS of NOS = –1
$$ \therefore $$ (+1)4 + x + (–1)5 + (–1)1 = 0
$$ \Rightarrow $$ x = +2
Na4[FeO4]
Let O.S. of Fe be y
(+1)4 + y + (–2)4 = 0
$$ \Rightarrow $$ y = +4
[Fe2(CO)9]
Let O.S. of Fe be z
2z + 0 × 9 = 0
$$ \Rightarrow $$ z = 0
so (x + y + z) = +2 + 4 + 0 = 6
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