JEE MAIN - Chemistry (2019 - 9th January Morning Slot - No. 8)
The correct match between Item-I and Item-II is :
| Item-I (drug) | Item-II (test) | ||
|---|---|---|---|
| A | Chloroxylenol | P | Carbylamine test |
| B | Norethindrone | Q | Sodium hydrogen carbonet test |
| C | Sulphapyridine | R | Ferric chloride test |
| D | Penicillin | S | Bayer's test |
A $$ \to $$ R; B $$ \to $$ P; C $$ \to $$ S; D $$ \to $$ Q
A $$ \to $$ Q; B $$ \to $$ S; C $$ \to $$ P; D $$ \to $$ R
A $$ \to $$ R; B $$ \to $$ S; C $$ \to $$ P; D $$ \to $$ Q
A $$ \to $$ Q; B $$ \to $$ P; C $$ \to $$ S; D $$ \to $$ R
Explanation
(1) To react with FeCl3, with benzene ring there should be a $$-$$OH group attached.
(2) For carbylamine test there should be $$-$$NH2 group in a compound.
(3) NaHCO3 reacts when there is $$-$$COOH group in a compound.
(4) For Bayer's test there should be double bond or tripple bond between two carbon.
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(2) For carbylamine test there should be $$-$$NH2 group in a compound.
(3) NaHCO3 reacts when there is $$-$$COOH group in a compound.
(4) For Bayer's test there should be double bond or tripple bond between two carbon.
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