JEE MAIN - Chemistry (2019 - 9th January Morning Slot - No. 20)
The highest value of the calculated spin only magnetic moment (in BM) among all the transition metal complexes is :
5.92
6.93
3.87
4.90
Explanation
In transition metal contains d orbital, and in d orbital maximum no of unpaired electron possible = 5.
Spin only magnetic moment,
$${\mu _{spin}} = \sqrt {n\left( {n + 2} \right)} $$ B. M
here n $$=$$ Number of unpaired electrons.
$$ \therefore $$ $${\mu _{spin}} = \sqrt {5\left( {5 + 2} \right)} $$ B. M
$$=$$ 5.92 B. M
Spin only magnetic moment,
$${\mu _{spin}} = \sqrt {n\left( {n + 2} \right)} $$ B. M
here n $$=$$ Number of unpaired electrons.
$$ \therefore $$ $${\mu _{spin}} = \sqrt {5\left( {5 + 2} \right)} $$ B. M
$$=$$ 5.92 B. M
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