JEE MAIN - Chemistry (2019 - 9th January Evening Slot - No. 1)
The increasing basicity order of the following compounds is :
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A < B < D < C
D < C < A < B
D < C < B < A
A < B < C < D
Explanation
(A) In the first compound, because of +I effect of CH3CH2- group electron density increses on N atom.
(B) In the second compound, because of +I effect of two CH3CH2- group electron density is more on N atom than first compound so it is more basic than compound A.
(C) Three -CH3 group creates steric hindrance around N atom, for that reason N atom can't donate lone pair easily.
(D) Here lone pair of N atom, perticipate in resonance with benzene ring so N atom can't donate lone pair. That is why it is least basic among this four compounds.
So correct order is D < C < A < B.
(B) In the second compound, because of +I effect of two CH3CH2- group electron density is more on N atom than first compound so it is more basic than compound A.
(C) Three -CH3 group creates steric hindrance around N atom, for that reason N atom can't donate lone pair easily.
(D) Here lone pair of N atom, perticipate in resonance with benzene ring so N atom can't donate lone pair. That is why it is least basic among this four compounds.
So correct order is D < C < A < B.
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