JEE MAIN - Chemistry (2019 - 9th April Evening Slot - No. 7)
Consider the given plot of enthalpy of the
following reaction between A and B.
A+ B $$ \to $$ C + D
Identify the incorrect statement._9th_April_Evening_Slot_en_7_2.png)
A+ B $$ \to $$ C + D
Identify the incorrect statement.
_9th_April_Evening_Slot_en_7_2.png)
Formation of A and B from C has highest
enthalpy of activation.
D is kinetically stable product.
C is the thermodynamically stable product
Activation enthalpy to form C is 5kJ molā1
less than that to form D.
Explanation
_9th_April_Evening_Slot_en_7_4.png)
$$ \therefore $$ E$$a$$ = (A + B) $$ \to $$ C = 15
E$$a$$ = (A + B) $$ \to $$ D = 10
So, Activation enthalpy to form C is 5 kJ mol-1 more than that to form D.
Comments (0)
