JEE MAIN - Chemistry (2019 - 9th April Evening Slot - No. 16)
During compression of a spring the work done
is 10kJ and 2kJ escaped to the surroundings as
heat. The change in internal energy, $$\Delta $$U(inkJ)
is :
- 12
8
- 8
12
Explanation
Here heat is released so q is negative.
$$ \therefore $$ q = - 2 kJ
Work done on the system, w = 10 kJ
From first law of thermodynamics,
$$\Delta $$U = q + w = -2 + 10 = 8 kJ
$$ \therefore $$ q = - 2 kJ
Work done on the system, w = 10 kJ
From first law of thermodynamics,
$$\Delta $$U = q + w = -2 + 10 = 8 kJ
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