JEE MAIN - Chemistry (2019 - 9th April Evening Slot - No. 1)

Hinsberg's reagent is :
C6H5COCl
C6H5SO2Cl
SOCl2
(COCl)2

Explanation

The correct answer is Option B: C6H5SO2Cl.

Hinsberg's reagent is benzenesulfonyl chloride (C6H5SO2Cl). It is used to differentiate primary, secondary, and tertiary amines.

Here's why the other options are incorrect :

  • Option A: C6H5COCl is benzoyl chloride, a reagent used in Friedel-Crafts acylation reactions.

  • Option C: SOCl2 is thionyl chloride, a reagent used to convert alcohols into alkyl chlorides.

  • Option D: (COCl)2 is oxalyl chloride, a reagent used for the conversion of carboxylic acids into acid chlorides.

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