JEE MAIN - Chemistry (2019 - 9th April Evening Slot - No. 1)
Hinsberg's reagent is :
C6H5COCl
C6H5SO2Cl
SOCl2
(COCl)2
Explanation
The correct answer is Option B: C6H5SO2Cl.
Hinsberg's reagent is benzenesulfonyl chloride (C6H5SO2Cl). It is used to differentiate primary, secondary, and tertiary amines.
Here's why the other options are incorrect :
- Option A: C6H5COCl is benzoyl chloride, a reagent used in Friedel-Crafts acylation reactions.
- Option C: SOCl2 is thionyl chloride, a reagent used to convert alcohols into alkyl chlorides.
- Option D: (COCl)2 is oxalyl chloride, a reagent used for the conversion of carboxylic acids into acid chlorides.
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