JEE MAIN - Chemistry (2019 - 8th April Morning Slot - No. 2)
The following ligand is :
_8th_April_Morning_Slot_en_2_1.png)
_8th_April_Morning_Slot_en_2_1.png)
hexadentate
bidentate
tetradentate
tridentate
Explanation
Here two O- + two N = 4 donar atoms present which can donate total 4 lone pair of electrons.
$$ \therefore $$ It is tetradentate ligand.
$$ \therefore $$ It is tetradentate ligand.
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