JEE MAIN - Chemistry (2019 - 8th April Morning Slot - No. 19)
If solublity product of Zr3(PO4)4 is denoted by Ksp and its molar solubility is denoted by S, then
which of the following relation between S and Ksp is correct ?
$$S = {\left( {{{{K_{sp}}} \over {929}}} \right)^{1/9}}$$
$$S = {\left( {{{{K_{sp}}} \over {6912}}} \right)^{1/7}}$$
$$S = {\left( {{{{K_{sp}}} \over {144}}} \right)^{1/6}}$$
$$S = {\left( {{{{K_{sp}}} \over {216}}} \right)^{1/7}}$$
Explanation
| Zr3(PO4)4 | ā | 3Zr+4 | + | 4PO4-3 |
|---|---|---|---|---|
| S | 3S | 4S |
Ksp = [Zr+4]3 [PO4-3]4
= [3S]3 [4S]4
= 27S3 $$ \times $$ 256S4
= 6912S7
$$ \therefore $$ $$S = {\left( {{{{K_{sp}}} \over {6912}}} \right)^{1/7}}$$
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