JEE MAIN - Chemistry (2019 - 8th April Morning Slot - No. 12)
The quantum number of four electrons are given below :
n = 4, l = 2, ml =–2, ms = –1/2
n = 3, l = 2, ml = 1, ms = +1/2
n = 4, l = 1, ml = 0, ms = +1/2
n = 3, l = 1, ml = 1, ms = –1/2
The correct order of their increasing enegies will be :
n = 4, l = 2, ml =–2, ms = –1/2
n = 3, l = 2, ml = 1, ms = +1/2
n = 4, l = 1, ml = 0, ms = +1/2
n = 3, l = 1, ml = 1, ms = –1/2
The correct order of their increasing enegies will be :
IV < II < III < I
I < III < II < IV
IV < III < II < I
I < II < III < IV
Explanation
n = 4, l = 2, 4d orbital, n + l = 6
n = 3, l = 2, 3d orbital, n + l = 5
n = 4, l = 1, 4p orbital, n + l = 5
n = 3, l = 1, 3p orbital, n + l = 4
more is n + l value, more is energy
$$ \therefore $$ 3p < 3d < 4p < 4d
n = 3, l = 2, 3d orbital, n + l = 5
n = 4, l = 1, 4p orbital, n + l = 5
n = 3, l = 1, 3p orbital, n + l = 4
more is n + l value, more is energy
$$ \therefore $$ 3p < 3d < 4p < 4d
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