JEE MAIN - Chemistry (2019 - 8th April Evening Slot - No. 1)
For the solution of the gases w, x, y and z in
water at 298K, the Henrys law constants (KH)
are 0.5, 2, 35 and 40 kbar, respectively. The
correct plot for the given data is :-
_8th_April_Evening_Slot_en_1_1.png)
_8th_April_Evening_Slot_en_1_2.png)
_8th_April_Evening_Slot_en_1_3.png)
_8th_April_Evening_Slot_en_1_4.png)
Explanation
Henry's law expression,
Pgas = KH $$ \times $$ xgas
Here, Pgas = partial pressure of gas
KH = Henry’s law constant
xgas = mole fraction of gas
$$ \because $$ xgas = 1 - xH2O
$$ \therefore $$ Pgas = KH $$ \times $$ (1 - xH2O)
$$ \Rightarrow $$ Pgas = KH - KH $$ \times $$xH2O
By comparing this equation with y = mx + c,
c = KH = Intercept
m = - KH = slope
So in partial pressure vs mole fraction of water graph, which gas has more KH will have more intercept. Given (KH) are 0.5, 2, 35 and 40 kbar for w, x, y, z respectively. So intercept of z should be the most and should be the least.
As solpe is = - KH, so slope shoul be negative for all the gases and w gas should have least negative slope and z should have highest negative slope.
Pgas = KH $$ \times $$ xgas
Here, Pgas = partial pressure of gas
KH = Henry’s law constant
xgas = mole fraction of gas
$$ \because $$ xgas = 1 - xH2O
$$ \therefore $$ Pgas = KH $$ \times $$ (1 - xH2O)
$$ \Rightarrow $$ Pgas = KH - KH $$ \times $$xH2O
By comparing this equation with y = mx + c,
c = KH = Intercept
m = - KH = slope
So in partial pressure vs mole fraction of water graph, which gas has more KH will have more intercept. Given (KH) are 0.5, 2, 35 and 40 kbar for w, x, y, z respectively. So intercept of z should be the most and should be the least.
As solpe is = - KH, so slope shoul be negative for all the gases and w gas should have least negative slope and z should have highest negative slope.
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