As here HBr is present in excess, so HBr will react to alkene and ether part sinultaneously.

According to Markovnikov rule. Carbocation close to benzene ring is more stable.

In the given reagent, carbocation is $$ \to $$


So in HBr, Br^$$-$$ adds to the carbocation.

And in the ether part because of lone pair of oxygen, it will take part in resonance a double bond will create between O atom and benzene ring. So, this bond will be stronger. That is why CH₃ $$-$$ O bond will break.