JEE MAIN - Chemistry (2019 - 12th January Evening Slot - No. 1)
The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 BM. The suitable ligand for this complex is -
CN$$-$$
ethylenediamine
NCSā
CO
Explanation
Given, $$\mu $$ = 5.9 BM
$$ \therefore $$ n = number of unpaired electron = 5
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For Mn+2 with 5 unpaired electronic configuration only possible when ligand is weak field ligand.
Here weak field ligand is NCS$$-$$.
$$ \therefore $$ n = number of unpaired electron = 5
For Mn+2 with 5 unpaired electronic configuration only possible when ligand is weak field ligand.
Here weak field ligand is NCS$$-$$.
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