JEE MAIN - Chemistry (2019 - 12th April Morning Slot - No. 8)
The complex ion that will lose its crystal field stabilization energy upon oxidation of its metal to +3 state is :
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[Fe(phen)3]2+
[Zn(phen)3]2+
[Co(phen)3]2+
[Ni(phen)3]2+
Explanation
[Fe(phen)3]2+ $$ \to $$ [Fe(phen)3]3+
Here for Fe+2(3d6) :
CFSE = (-0.4 $$ \times $$ 4 + 0.6 $$ \times $$ 2)$$\Delta $$0
= -0.4$$\Delta $$0
for Fe+3(3d5) :
CFSE = (-0.4 $$ \times $$ 3 + 0.6 $$ \times $$ 2)$$\Delta $$0
= 0
Here crystal field stabilization energy(CFSE) decreses.
Here for Fe+2(3d6) :
CFSE = (-0.4 $$ \times $$ 4 + 0.6 $$ \times $$ 2)$$\Delta $$0
= -0.4$$\Delta $$0
for Fe+3(3d5) :
CFSE = (-0.4 $$ \times $$ 3 + 0.6 $$ \times $$ 2)$$\Delta $$0
= 0
Here crystal field stabilization energy(CFSE) decreses.
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