JEE MAIN - Chemistry (2019 - 12th April Morning Slot - No. 16)
An organic compound 'A' is oxidizod with Na2O2 followed by boiling with HNO3. The resultant solution is
then treated with ammonium molybdate to yield a yellow precipitate.
Based on above observation, the element present in the given compound is:
Based on above observation, the element present in the given compound is:
Fluorine
Phosphorus
Nitrogen
Sulphur
Explanation
Phosphorus is detected in the form of canary
yellow ppt on reaction with ammonium
molybdate.
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