JEE MAIN - Chemistry (2019 - 12th April Evening Slot - No. 15)
The coordination numbers of Co and Al in [Co(Cl)(en)2]Cl and K3[Al(C2O4)3], respectively, are :
(en = ethane-1, 2-diamine)
3 and 3
6 and 6
5 and 3
5 and 6
Explanation
Here in [Co(Cl)(en)2]Cl
'Cl' is monodentate so one coordinate linkage will be made with Co.
'en' is bidentate so two coordinate linkage will be made with Co. There are two 'en ' present so 4 coordinate linkage will be made with Co.
$$ \therefore $$ Total 5 coordinate linkage will be made with Co by Cl and en. So C.N. of Co is 5.
Here in K3[Al(C2O4)3]
C2O4-2 is bidentate so two coordinate linkage will be made with Al. There are three C2O4-2' present so 6 coordinate linkage will be made with Al.
$$ \therefore $$ So C.N. of Al is 6.
'Cl' is monodentate so one coordinate linkage will be made with Co.
'en' is bidentate so two coordinate linkage will be made with Co. There are two 'en ' present so 4 coordinate linkage will be made with Co.
$$ \therefore $$ Total 5 coordinate linkage will be made with Co by Cl and en. So C.N. of Co is 5.
Here in K3[Al(C2O4)3]
C2O4-2 is bidentate so two coordinate linkage will be made with Al. There are three C2O4-2' present so 6 coordinate linkage will be made with Al.
$$ \therefore $$ So C.N. of Al is 6.
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