JEE MAIN - Chemistry (2019 - 12th April Evening Slot - No. 13)
The INCORRECT match in the following is :
$$\Delta $$Go
= 0, K = 1
$$\Delta $$Go
< 0, K < 1
$$\Delta $$Go
> 0, K < 1
$$\Delta $$Go
< 0, K > 1
Explanation
We know, $$\Delta {G^o} = - RT\ln K$$
Case 1 :
If $$\Delta $$Go < 0
$$ \Rightarrow $$ $$- RT\ln K$$ < 0
$$ \Rightarrow $$ $$\ln K$$ > 0
$$ \Rightarrow $$ K > 1
Case 2 :
If $$\Delta $$Go > 0
$$ \Rightarrow $$ $$- RT\ln K$$ > 0
$$ \Rightarrow $$ $$\ln K$$ < 0
$$ \Rightarrow $$ K < 1
Case 2 :
If $$\Delta $$Go = 0
$$ \Rightarrow $$ $$- RT\ln K$$ = 0
$$ \Rightarrow $$ $$\ln K$$ = 0
$$ \Rightarrow $$ K = 1
Case 1 :
If $$\Delta $$Go < 0
$$ \Rightarrow $$ $$- RT\ln K$$ < 0
$$ \Rightarrow $$ $$\ln K$$ > 0
$$ \Rightarrow $$ K > 1
Case 2 :
If $$\Delta $$Go > 0
$$ \Rightarrow $$ $$- RT\ln K$$ > 0
$$ \Rightarrow $$ $$\ln K$$ < 0
$$ \Rightarrow $$ K < 1
Case 2 :
If $$\Delta $$Go = 0
$$ \Rightarrow $$ $$- RT\ln K$$ = 0
$$ \Rightarrow $$ $$\ln K$$ = 0
$$ \Rightarrow $$ K = 1
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