JEE MAIN - Chemistry (2019 - 11th January Evening Slot - No. 14)
A compound 'X' on treatment with Br2/NaOH, provided C3H9N, which gives positive carbylamine test. Compound 'X' is :
CH3CH2CH2CONH2
CH3CON(CH3)2
CH3CH2COCH2NH
CH3COCH2NHCH3
Explanation
Br2/NaOH(Hoffman Hypobromide reagent) converts amide into primary amine having one carbon atom less, which gives
carbylamine test. In the Amide there should be
-CONH2 group to produce primary amine.
-CONH2 group to produce primary amine.
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