JEE MAIN - Chemistry (2019 - 10th January Morning Slot - No. 1)
The major product of the following reaction is :
_10th_January_Morning_Slot_en_1_1.png)
_10th_January_Morning_Slot_en_1_2.png)
_10th_January_Morning_Slot_en_1_3.png)
_10th_January_Morning_Slot_en_1_4.png)
_10th_January_Morning_Slot_en_1_5.png)
Explanation
In the given reaction, $$\mathrm{AlCl}_{3}$$ acts as Lewis acid and helps in the generation of the carbocation. The resulting carbocation $$\left(1^{\circ}\right)$$ rearranges itself to stable carbocation $$\left(3^{\circ}\right)$$.
_10th_January_Morning_Slot_en_1_6.png)
Comments (0)
