JEE MAIN - Chemistry (2019 - 10th January Evening Slot - No. 13)
The correct match between item 'I' and item 'II' is :
| Item 'I' (compound) | Item 'II' (reagent) |
||
|---|---|---|---|
| (A) | Lysine | (P) | 1-naphthol |
| (B) | Furfural | (Q) | ninhydrin |
| (C) | Benzylalcohol | (R) | KMnO4 |
| (D) | Styrene | (S) | Ceric ammonium nitrate |
(A) $$ \to $$ (Q); (B) $$ \to $$ (R); (C) $$ \to $$ (S);
(D) $$ \to $$ (P)
(A) $$ \to $$ (Q); (B) $$ \to $$ (P); (C) $$ \to $$ (S);
(D) $$ \to $$ (R)
(A) $$ \to $$ (R); (B) $$ \to $$ (P); (C) $$ \to $$ (Q);
(D) $$ \to $$ (S)
(A) $$ \to $$ (Q); (B) $$ \to $$ (P); (C) $$ \to $$ (R);
(D) $$ \to $$ (S)
Explanation
Lysine is an amino acid which gives nindydrin test.
Furfural has aldehyde group that is why it reacts with 1-napthol to give purple colouration.
Benzyl alcohol undergoes reaction with ceric ammonium nitrate to give pink colouration.
Styrene reacts with KMnO4 and gives benzoic acid and brown MnO2.
Furfural has aldehyde group that is why it reacts with 1-napthol to give purple colouration.
Benzyl alcohol undergoes reaction with ceric ammonium nitrate to give pink colouration.
Styrene reacts with KMnO4 and gives benzoic acid and brown MnO2.
Comments (0)
