JEE MAIN - Chemistry (2019 - 10th April Evening Slot - No. 1)
The increasing order of nucleophilicity of the following nucleophiles is :
(a) CH3CO2$$-$$ (b) H2O
(c) CH3SO3$$-$$ (d) $$\mathop O\limits^ - H$$
(a) CH3CO2$$-$$ (b) H2O
(c) CH3SO3$$-$$ (d) $$\mathop O\limits^ - H$$
(b) < (c) < (a) < (d)
(b) < (c) < (d) < (a)
(a) < (d) < (c) < (b)
(d) < (a) < (c) < (b)
Explanation
When stability of nucleophile increases then nucleophilicity decreases.
Stability order :
H2O > CH3SO3$$-$$ > CH3CO2$$-$$ > $$\mathop O\limits^ - H$$
So Nucleophilicity order :
H2O < CH3SO3$$-$$ < CH3CO2$$-$$ < $$\mathop O\limits^ - H$$
Stability order :
H2O > CH3SO3$$-$$ > CH3CO2$$-$$ > $$\mathop O\limits^ - H$$
So Nucleophilicity order :
H2O < CH3SO3$$-$$ < CH3CO2$$-$$ < $$\mathop O\limits^ - H$$
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